(35-5/20-5)=(0.05-0.2/x-0.05)

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Solution for (35-5/20-5)=(0.05-0.2/x-0.05) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

35-(5/20)-5 = 0.05-(0.2/x)-0.05 // - 0.05-(0.2/x)-0.05

0.2/x-(5/20)-5-0.05+0.05+35 = 0

0.2/x-1/4-5-0.05+0.05+35 = 0

0.2*x^-1 = -29.75 // : 0.2

x^-1 = -148.75

-1 < 0

1/(x^1) = -148.75 // * x^1

1 = -148.75*x^1 // : -148.75

-0.00672269 = x^1

x = -0.00672269

x = -0.00672269

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