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(36+2x)(30+2x)=1880
We move all terms to the left:
(36+2x)(30+2x)-(1880)=0
We add all the numbers together, and all the variables
(2x+36)(2x+30)-1880=0
We multiply parentheses ..
(+4x^2+60x+72x+1080)-1880=0
We get rid of parentheses
4x^2+60x+72x+1080-1880=0
We add all the numbers together, and all the variables
4x^2+132x-800=0
a = 4; b = 132; c = -800;
Δ = b2-4ac
Δ = 1322-4·4·(-800)
Δ = 30224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{30224}=\sqrt{16*1889}=\sqrt{16}*\sqrt{1889}=4\sqrt{1889}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-4\sqrt{1889}}{2*4}=\frac{-132-4\sqrt{1889}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+4\sqrt{1889}}{2*4}=\frac{-132+4\sqrt{1889}}{8} $
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