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(36+2x)(30+2x)=800
We move all terms to the left:
(36+2x)(30+2x)-(800)=0
We add all the numbers together, and all the variables
(2x+36)(2x+30)-800=0
We multiply parentheses ..
(+4x^2+60x+72x+1080)-800=0
We get rid of parentheses
4x^2+60x+72x+1080-800=0
We add all the numbers together, and all the variables
4x^2+132x+280=0
a = 4; b = 132; c = +280;
Δ = b2-4ac
Δ = 1322-4·4·280
Δ = 12944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12944}=\sqrt{16*809}=\sqrt{16}*\sqrt{809}=4\sqrt{809}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-4\sqrt{809}}{2*4}=\frac{-132-4\sqrt{809}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+4\sqrt{809}}{2*4}=\frac{-132+4\sqrt{809}}{8} $
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