(36+2x)(48+2x)=0

Solution for (36+2x)(48+2x)=0 equation:

(36+2x)(48+2x)=0

We add all the numbers together, and all the variables

(2x+36)(2x+48)=0

We multiply parentheses ..

(+4x^2+96x+72x+1728)=0

We get rid of parentheses

4x^2+96x+72x+1728=0

We add all the numbers together, and all the variables

4x^2+168x+1728=0

a = 4; b = 168; c = +1728;
Δ = b2-4ac
Δ = 1682-4·4·1728
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-24}{2*4}=\frac{-192}{8}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+24}{2*4}=\frac{-144}{8}
=-18
$