(36+x)*(60-x)=2295

Solution for (36+x)*(60-x)=2295 equation:

(36+x)(60-x)=2295

We move all terms to the left:

(36+x)(60-x)-(2295)=0

We add all the numbers together, and all the variables

(x+36)(-1x+60)-2295=0

We multiply parentheses ..

(-1x^2+60x-36x+2160)-2295=0

We get rid of parentheses

-1x^2+60x-36x+2160-2295=0

We add all the numbers together, and all the variables

-1x^2+24x-135=0

a = -1; b = 24; c = -135;
Δ = b2-4ac
Δ = 242-4·(-1)·(-135)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6}{2*-1}=\frac{-30}{-2}
=+15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6}{2*-1}=\frac{-18}{-2}
=+9
$