(39)/(6t-23)

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Solution for (39)/(6t-23) equation: 


D( t )

6*t-23 = 0

6*t-23 = 0

6*t-23 = 0

6*t-23 = 0 // + 23

6*t = 23 // : 6

t = 23/6

t in (-oo:23/6) U (23/6:+oo)

39/(6*t-23) = 0

t belongs to the empty set

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