(3=2i)+(4-5i)

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Solution for (3=2i)+(4-5i) equation:



(3=2i)+(4-5i)
We move all terms to the left:
(3-(2i)+(4-5i))=0
We add all the numbers together, and all the variables
(3-2i+(-5i+4))=0
We calculate terms in parentheses: +(3-2i+(-5i+4)), so:
3-2i+(-5i+4)
determiningTheFunctionDomain -2i+(-5i+4)+3
We get rid of parentheses
-2i-5i+4+3
We add all the numbers together, and all the variables
-7i+7
Back to the equation:
+(-7i+7)
We get rid of parentheses
-7i+7=0
We move all terms containing i to the left, all other terms to the right
-7i=-7
i=-7/-7
i=1

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