(3=2i)+(5-3i)

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Solution for (3=2i)+(5-3i) equation: 



(3=2i)+(5-3i)

We move all terms to the left:

(3-(2i)+(5-3i))=0

We add all the numbers together, and all the variables

(3-2i+(-3i+5))=0



We calculate terms in parentheses: +(3-2i+(-3i+5)), so:

3-2i+(-3i+5)

determiningTheFunctionDomain
-2i+(-3i+5)+3

We get rid of parentheses

-2i-3i+5+3

We add all the numbers together, and all the variables

-5i+8

Back to the equation:

+(-5i+8)



We get rid of parentheses

-5i+8=0

We move all terms containing i to the left, all other terms to the right

-5i=-8

i=-8/-5

i=1+3/5

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