(3=2i)+(7+3i)

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Solution for (3=2i)+(7+3i) equation: 



(3=2i)+(7+3i)

We move all terms to the left:

(3-(2i)+(7+3i))=0

We add all the numbers together, and all the variables

(3-2i+(3i+7))=0



We calculate terms in parentheses: +(3-2i+(3i+7)), so:

3-2i+(3i+7)

determiningTheFunctionDomain
-2i+(3i+7)+3

We get rid of parentheses

-2i+3i+7+3

We add all the numbers together, and all the variables

i+10

Back to the equation:

+(i+10)



We get rid of parentheses

i+10=0

We move all terms containing i to the left, all other terms to the right

i=-10

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