(3D+3)=2d+2(d-5)

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Solution for (3D+3)=2d+2(d-5) equation: 



(3+3)=2D+2(D-5)

We move all terms to the left:

(3+3)-(2D+2(D-5))=0

We add all the numbers together, and all the variables

-(2D+2(D-5))+6=0



We calculate terms in parentheses: -(2D+2(D-5)), so:

2D+2(D-5)

We multiply parentheses

2D+2D-10

We add all the numbers together, and all the variables

4D-10

Back to the equation:

-(4D-10)



We get rid of parentheses

-4D+10+6=0

We add all the numbers together, and all the variables

-4D+16=0

We move all terms containing D to the left, all other terms to the right

-4D=-16

D=-16/-4

D=+4

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