(3R+6)/8=(2r+10)/6

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Solution for (3R+6)/8=(2r+10)/6 equation: 



(3+6)/8=(2R+10)/6

We move all terms to the left:

(3+6)/8-((2R+10)/6)=0

We add all the numbers together, and all the variables

-((2R+10)/6)+9/8=0

We calculate fractions


(-((2R+10)*8)/()+()/()=0



We calculate terms in parentheses: +(-((2R+10)*8)/()+()/(), so:

-((2R+10)*8)/()+()/(

We add all the numbers together, and all the variables

-((2R+10)*8)/()+1

We multiply all the terms by the denominator


-((2R+10)*8)+1*()



We calculate terms in parentheses: -((2R+10)*8), so:

(2R+10)*8

We multiply parentheses

16R+80

Back to the equation:

-(16R+80)



We add all the numbers together, and all the variables

-(16R+80)

We get rid of parentheses

-16R-80

Back to the equation:

+(-16R-80)



We get rid of parentheses

-16R-80=0

We move all terms containing R to the left, all other terms to the right

-16R=80

R=80/-16

R=-5

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