(3V+2)-(V-+1)=V+(2v+3)

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Solution for (3V+2)-(V-+1)=V+(2v+3) equation: 



(3+2)-(-+1)=+(2V+3)

We move all terms to the left:

(3+2)-(-+1)-(+(2V+3))=0

We add all the numbers together, and all the variables

-(+(2V+3))+5-0=0

We add all the numbers together, and all the variables

-(+(2V+3))+5=0



We calculate terms in parentheses: -(+(2V+3)), so:

+(2V+3)

determiningTheFunctionDomain
(2V+3)

We get rid of parentheses

2V+3

Back to the equation:

-(2V+3)



We get rid of parentheses

-2V-3+5=0

We add all the numbers together, and all the variables

-2V+2=0

We move all terms containing V to the left, all other terms to the right

-2V=-2

V=-2/-2

V=1

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