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X in (-oo:+oo)
(3*X+1)/3 = (5*X+1)/5 // - (5*X+1)/5
(3*X+1)/3-((5*X+1)/5) = 0
(3*X+1)/3+(-1*(5*X+1))/5 = 0
(5*(3*X+1))/(3*5)+(-1*3*(5*X+1))/(3*5) = 0
5*(3*X+1)-1*3*(5*X+1) = 0
2 = 0
2/(3*5) = 0
2/(3*5) = 0 // * 3*5
2 = 0
X belongs to the empty set
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