(3X+3)+(4x)=45

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Solution for (3X+3)+(4x)=45 equation: 



(3X+3)+(4X)=45

We move all terms to the left:

(3X+3)+(4X)-(45)=0

We add all the numbers together, and all the variables

4X+(3X+3)-45=0

We get rid of parentheses

4X+3X+3-45=0

We add all the numbers together, and all the variables

7X-42=0

We move all terms containing X to the left, all other terms to the right

7X=42

X=42/7

X=6

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