(3X+Y)+(X+3y)=19+1

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Solution for (3X+Y)+(X+3y)=19+1 equation: 



(3X+)+(X+3X)=19+1

We move all terms to the left:

(3X+)+(X+3X)-(19+1)=0

We add all the numbers together, and all the variables

(+3X)+(+4X)-20=0

We get rid of parentheses

3X+4X-20=0

We add all the numbers together, and all the variables

7X-20=0

We move all terms containing X to the left, all other terms to the right

7X=20

X=20/7

X=2+6/7

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