(3Z/5)-((Z-3)/2)=(Z+2)/3

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Solution for (3Z/5)-((Z-3)/2)=(Z+2)/3 equation: 


Z in (-oo:+oo)

(3*Z)/5-((Z-3)/2) = (Z+2)/3 // - (Z+2)/3

(3*Z)/5-((Z-3)/2)-((Z+2)/3) = 0

(-1*(Z-3))/2+(-1*(Z+2))/3+(3*Z)/5 = 0

(-1*3*5*(Z-3))/(2*3*5)+(-1*2*5*(Z+2))/(2*3*5)+(2*3*3*Z)/(2*3*5) = 0

2*3*3*Z-1*3*5*(Z-3)-1*2*5*(Z+2) = 0

18*Z-25*Z+25 = 0

25-7*Z = 0

(25-7*Z)/(2*3*5) = 0

(25-7*Z)/(2*3*5) = 0 // * 2*3*5

25-7*Z = 0

25-7*Z = 0 // - 25

-7*Z = -25 // : -7

Z = -25/(-7)

Z = 25/7

Z = 25/7

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