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(3a+1)(4a+8)=0
We multiply parentheses ..
(+12a^2+24a+4a+8)=0
We get rid of parentheses
12a^2+24a+4a+8=0
We add all the numbers together, and all the variables
12a^2+28a+8=0
a = 12; b = 28; c = +8;
Δ = b2-4ac
Δ = 282-4·12·8
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-20}{2*12}=\frac{-48}{24} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+20}{2*12}=\frac{-8}{24} =-1/3 $
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