(3a+1)+a(2a-5)=

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Solution for (3a+1)+a(2a-5)= equation: 



(3a+1)+a(2a-5)=

We move all terms to the left:

(3a+1)+a(2a-5)-()=0

We add all the numbers together, and all the variables

(3a+1)+a(2a-5)=0

We multiply parentheses

2a^2+(3a+1)-5a=0

We get rid of parentheses

2a^2+3a-5a+1=0

We add all the numbers together, and all the variables

2a^2-2a+1=0

a = 2; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·2·1
Δ = -4
Delta is less than zero, so there is no solution for the equation

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