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(3a+1)=(2a+1)
We move all terms to the left:
(3a+1)-((2a+1))=0
We get rid of parentheses
3a-((2a+1))+1=0
We calculate terms in parentheses: -((2a+1)), so:We get rid of parentheses
(2a+1)
We get rid of parentheses
2a+1
Back to the equation:
-(2a+1)
3a-2a-1+1=0
We add all the numbers together, and all the variables
a=0
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