(3a+15)=(a+35)=

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Solution for (3a+15)=(a+35)= equation: 



(3a+15)=(a+35)=

We move all terms to the left:

(3a+15)-((a+35))=0

We get rid of parentheses

3a-((a+35))+15=0



We calculate terms in parentheses: -((a+35)), so:

(a+35)

We get rid of parentheses

a+35

Back to the equation:

-(a+35)



We get rid of parentheses

3a-a-35+15=0

We add all the numbers together, and all the variables

2a-20=0

We move all terms containing a to the left, all other terms to the right

2a=20

a=20/2

a=10

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