(3a+2)(5a+2)=6a+4

Solution for (3a+2)(5a+2)=6a+4 equation:

(3a+2)(5a+2)=6a+4

We move all terms to the left:

(3a+2)(5a+2)-(6a+4)=0

We get rid of parentheses

(3a+2)(5a+2)-6a-4=0

We multiply parentheses ..

(+15a^2+6a+10a+4)-6a-4=0

We get rid of parentheses

15a^2+6a+10a-6a+4-4=0

We add all the numbers together, and all the variables

15a^2+10a=0

a = 15; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·15·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*15}=\frac{-20}{30}
=-2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*15}=\frac{0}{30}
=0
$