(3a+29-5)+(-9-4a+4)=7

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Solution for (3a+29-5)+(-9-4a+4)=7 equation: 



(3a+29-5)+(-9-4a+4)=7

We move all terms to the left:

(3a+29-5)+(-9-4a+4)-(7)=0

We add all the numbers together, and all the variables

(3a+24)+(-4a-5)-7=0

We get rid of parentheses

3a-4a+24-5-7=0

We add all the numbers together, and all the variables

-1a+12=0

We move all terms containing a to the left, all other terms to the right

-a=-12

a=-12/-1

a=+12

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