(3a+4b-c)+(-2a+4b+3c)=

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Solution for (3a+4b-c)+(-2a+4b+3c)= equation:


Simplifying
(3a + 4b + -1c) + (-2a + 4b + 3c) = 0

Remove parenthesis around (3a + 4b + -1c)
3a + 4b + -1c + (-2a + 4b + 3c) = 0

Remove parenthesis around (-2a + 4b + 3c)
3a + 4b + -1c + -2a + 4b + 3c = 0

Reorder the terms:
3a + -2a + 4b + 4b + -1c + 3c = 0

Combine like terms: 3a + -2a = 1a
1a + 4b + 4b + -1c + 3c = 0

Combine like terms: 4b + 4b = 8b
1a + 8b + -1c + 3c = 0

Combine like terms: -1c + 3c = 2c
1a + 8b + 2c = 0

Solving
1a + 8b + 2c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8b' to each side of the equation.
1a + 8b + -8b + 2c = 0 + -8b

Combine like terms: 8b + -8b = 0
1a + 0 + 2c = 0 + -8b
1a + 2c = 0 + -8b
Remove the zero:
1a + 2c = -8b

Add '-2c' to each side of the equation.
1a + 2c + -2c = -8b + -2c

Combine like terms: 2c + -2c = 0
1a + 0 = -8b + -2c
1a = -8b + -2c

Divide each side by '1'.
a = -8b + -2c

Simplifying
a = -8b + -2c

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