(3a+4b-c)+(a+6b+4c)=

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Solution for (3a+4b-c)+(a+6b+4c)= equation:


Simplifying
(3a + 4b + -1c) + (a + 6b + 4c) = 0

Remove parenthesis around (3a + 4b + -1c)
3a + 4b + -1c + (a + 6b + 4c) = 0

Remove parenthesis around (a + 6b + 4c)
3a + 4b + -1c + a + 6b + 4c = 0

Reorder the terms:
3a + a + 4b + 6b + -1c + 4c = 0

Combine like terms: 3a + a = 4a
4a + 4b + 6b + -1c + 4c = 0

Combine like terms: 4b + 6b = 10b
4a + 10b + -1c + 4c = 0

Combine like terms: -1c + 4c = 3c
4a + 10b + 3c = 0

Solving
4a + 10b + 3c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-10b' to each side of the equation.
4a + 10b + -10b + 3c = 0 + -10b

Combine like terms: 10b + -10b = 0
4a + 0 + 3c = 0 + -10b
4a + 3c = 0 + -10b
Remove the zero:
4a + 3c = -10b

Add '-3c' to each side of the equation.
4a + 3c + -3c = -10b + -3c

Combine like terms: 3c + -3c = 0
4a + 0 = -10b + -3c
4a = -10b + -3c

Divide each side by '4'.
a = -2.5b + -0.75c

Simplifying
a = -2.5b + -0.75c

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