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(3a+6)(2a+10)=
We move all terms to the left:
(3a+6)(2a+10)-()=0
We add all the numbers together, and all the variables
(3a+6)(2a+10)=0
We multiply parentheses ..
(+6a^2+30a+12a+60)=0
We get rid of parentheses
6a^2+30a+12a+60=0
We add all the numbers together, and all the variables
6a^2+42a+60=0
a = 6; b = 42; c = +60;
Δ = b2-4ac
Δ = 422-4·6·60
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-18}{2*6}=\frac{-60}{12} =-5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+18}{2*6}=\frac{-24}{12} =-2 $
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