(3a+7/5)=2

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Solution for (3a+7/5)=2 equation: 



(3a+7/5)=2

We move all terms to the left:

(3a+7/5)-(2)=0

We add all the numbers together, and all the variables

(+3a+7/5)-2=0

We get rid of parentheses

3a-2+7/5=0

We multiply all the terms by the denominator


3a*5+7-2*5=0

We add all the numbers together, and all the variables

3a*5-3=0

Wy multiply elements

15a-3=0

We move all terms containing a to the left, all other terms to the right

15a=3

a=3/15

a=1/5

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