(3a-1)/8=(a+9)/4

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Solution for (3a-1)/8=(a+9)/4 equation:



(3a-1)/8=(a+9)/4
We move all terms to the left:
(3a-1)/8-((a+9)/4)=0
We calculate fractions
3a/()+(-((a+9)*8)/()=0
We calculate terms in parentheses: +(-((a+9)*8)/(), so:
-((a+9)*8)/(
We multiply all the terms by the denominator
-((a+9)*8)
We calculate terms in parentheses: -((a+9)*8), so:
(a+9)*8
We multiply parentheses
8a+72
Back to the equation:
-(8a+72)
We get rid of parentheses
-8a-72
Back to the equation:
+(-8a-72)
We get rid of parentheses
3a/()-8a-72=0
We multiply all the terms by the denominator
3a-8a*()-72*()=0
We add all the numbers together, and all the variables
3a-8a*()=0

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