(3a-10)(2a-7)=0

Solution for (3a-10)(2a-7)=0 equation:

(3a-10)(2a-7)=0

We multiply parentheses ..

(+6a^2-21a-20a+70)=0

We get rid of parentheses

6a^2-21a-20a+70=0

We add all the numbers together, and all the variables

6a^2-41a+70=0

a = 6; b = -41; c = +70;
Δ = b2-4ac
Δ = -412-4·6·70
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-1}{2*6}=\frac{40}{12}
=3+1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+1}{2*6}=\frac{42}{12}
=3+1/2
$