(3a-2)/(a-3)+(2a-3)/(a+7)=5

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Solution for (3a-2)/(a-3)+(2a-3)/(a+7)=5 equation: 



(3a-2)/(a-3)+(2a-3)/(a+7)=5

We move all terms to the left:

(3a-2)/(a-3)+(2a-3)/(a+7)-(5)=0



Domain of the equation: (a-3)!=0

We move all terms containing a to the left, all other terms to the right

a!=3

a∈R





Domain of the equation: (a+7)!=0

We move all terms containing a to the left, all other terms to the right

a!=-7

a∈R



We calculate fractions


((3a-2)*(a+7))/((a-3)*(a+7))+((2a-3)*(a-3))/((a-3)*(a+7))-5=0



We calculate terms in parentheses: +((3a-2)*(a+7))/((a-3)*(a+7)), so:

(3a-2)*(a+7))/((a-3)*(a+7)

We multiply all the terms by the denominator


(3a-2)*(a+7))

Back to the equation:

+((3a-2)*(a+7)))





We calculate terms in parentheses: +((2a-3)*(a-3))/((a-3)*(a+7)), so:

(2a-3)*(a-3))/((a-3)*(a+7)

We multiply all the terms by the denominator


(2a-3)*(a-3))

Back to the equation:

+((2a-3)*(a-3)))

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