(3a-3b)-(b+c)=

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Solution for (3a-3b)-(b+c)= equation:


Simplifying
(3a + -3b) + -1(b + c) = 0

Remove parenthesis around (3a + -3b)
3a + -3b + -1(b + c) = 0
3a + -3b + (b * -1 + c * -1) = 0
3a + -3b + (-1b + -1c) = 0

Combine like terms: -3b + -1b = -4b
3a + -4b + -1c = 0

Solving
3a + -4b + -1c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '4b' to each side of the equation.
3a + -4b + 4b + -1c = 0 + 4b

Combine like terms: -4b + 4b = 0
3a + 0 + -1c = 0 + 4b
3a + -1c = 0 + 4b
Remove the zero:
3a + -1c = 4b

Add 'c' to each side of the equation.
3a + -1c + c = 4b + c

Combine like terms: -1c + c = 0
3a + 0 = 4b + c
3a = 4b + c

Divide each side by '3'.
a = 1.333333333b + 0.3333333333c

Simplifying
a = 1.333333333b + 0.3333333333c

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