(3a-5)(a+6)=0

Solution for (3a-5)(a+6)=0 equation:

(3a-5)(a+6)=0

We multiply parentheses ..

(+3a^2+18a-5a-30)=0

We get rid of parentheses

3a^2+18a-5a-30=0

We add all the numbers together, and all the variables

3a^2+13a-30=0

a = 3; b = 13; c = -30;
Δ = b2-4ac
Δ = 132-4·3·(-30)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-23}{2*3}=\frac{-36}{6}
=-6
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+23}{2*3}=\frac{10}{6}
=1+2/3
$