(3a-5)*(a-4)=(a-3)*(3a-6)

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Solution for (3a-5)*(a-4)=(a-3)*(3a-6) equation: 



(3a-5)(a-4)=(a-3)(3a-6)

We move all terms to the left:

(3a-5)(a-4)-((a-3)(3a-6))=0

We multiply parentheses ..

(+3a^2-12a-5a+20)-((a-3)(3a-6))=0



We calculate terms in parentheses: -((a-3)(3a-6)), so:

(a-3)(3a-6)

We multiply parentheses ..

(+3a^2-6a-9a+18)

We get rid of parentheses

3a^2-6a-9a+18

We add all the numbers together, and all the variables

3a^2-15a+18

Back to the equation:

-(3a^2-15a+18)



We get rid of parentheses

3a^2-3a^2-12a-5a+15a+20-18=0

We add all the numbers together, and all the variables

-2a+2=0

We move all terms containing a to the left, all other terms to the right

-2a=-2

a=-2/-2

a=1

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