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x in (-oo:+oo)
(3*a-5)/b = b+1 // - b+1
(3*a-5)/b-b-1 = 0
(3*a-5)/b+(-b*b)/b+(-1*b)/b = 0
3*a-b*b-1*b-5 = 0
3*a-b^2-b-5 = 0
(3*a-b^2-b-5)/b = 0
(3*a-b^2-b-5)/b = 0 // * b
3*a-b^2-b-5 = 0
x belongs to the empty set
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