(3a/7)+(2/3)=(7/90

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Solution for (3a/7)+(2/3)=(7/90 equation:



(3a/7)+(2/3)=(7/90
We move all terms to the left:
(3a/7)+(2/3)-((7/90)=0
We add all the numbers together, and all the variables
(+3a/7)+(+2/3)-((+7/90)=0
We get rid of parentheses
3a/7+2/3-((+7/90)=0
We calculate fractions
7290a^2/()+()/()+()/()=0
We add all the numbers together, and all the variables
7290a^2/()+2=0
We multiply all the terms by the denominator
7290a^2+2*()=0
We add all the numbers together, and all the variables
7290a^2=0
a = 7290; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7290·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{14580}=0$

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