(3a=4a2+7a)

Solution for (3a=4a2+7a) equation:

(3a=4a^2+7a)

We move all terms to the left:

(3a-(4a^2+7a))=0


We calculate terms in parentheses: +(3a-(4a^2+7a)), so:

3a-(4a^2+7a)

We get rid of parentheses

-4a^2+3a-7a

We add all the numbers together, and all the variables

-4a^2-4a

Back to the equation:

+(-4a^2-4a)


We get rid of parentheses

-4a^2-4a=0

a = -4; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-4)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-4}=\frac{0}{-8}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-4}=\frac{8}{-8}
=-1
$