(3b)(3b-0)=0

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Solution for (3b)(3b-0)=0 equation: 



(3b)(3b-0)=0

We add all the numbers together, and all the variables

3b(+3b)=0

We multiply parentheses

9b^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{18}=0$

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