(3b+1)/4+(b-5)/2=(4b-3)/8

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Solution for (3b+1)/4+(b-5)/2=(4b-3)/8 equation: 


b in (-oo:+oo)

(3*b+1)/4+(b-5)/2 = (4*b-3)/8 // - (4*b-3)/8

(3*b+1)/4+(b-5)/2-((4*b-3)/8) = 0

(3*b+1)/4+(b-5)/2+(-1*(4*b-3))/8 = 0

(2*8*(3*b+1))/(2*4*8)+(4*8*(b-5))/(2*4*8)+(-1*2*4*(4*b-3))/(2*4*8) = 0

2*8*(3*b+1)+4*8*(b-5)-1*2*4*(4*b-3) = 0

80*b-32*b-144+24 = 0

48*b-120 = 0

(48*b-120)/(2*4*8) = 0

(48*b-120)/(2*4*8) = 0 // * 2*4*8

48*b-120 = 0

48*b-120 = 0 // + 120

48*b = 120 // : 48

b = 120/48

b = 5/2

b = 5/2

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