(3b+1)=(5b-4)/3

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Solution for (3b+1)=(5b-4)/3 equation: 


b in (-oo:+oo)

3*b+1 = (5*b-4)/3 // - (5*b-4)/3

3*b-((5*b-4)/3)+1 = 0

(-1*(5*b-4))/3+3*b+1 = 0

(-1*(5*b-4))/3+(3*3*b)/3+(1*3)/3 = 0

3*3*b-1*(5*b-4)+1*3 = 0

4*b+3+4 = 0

4*b+7 = 0

(4*b+7)/3 = 0

(4*b+7)/3 = 0 // * 3

4*b+7 = 0

4*b+7 = 0 // - 7

4*b = -7 // : 4

b = -7/4

b = -7/4

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