(3b+2)=(2b+1)

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Solution for (3b+2)=(2b+1) equation: 



(3b+2)=(2b+1)

We move all terms to the left:

(3b+2)-((2b+1))=0

We get rid of parentheses

3b-((2b+1))+2=0



We calculate terms in parentheses: -((2b+1)), so:

(2b+1)

We get rid of parentheses

2b+1

Back to the equation:

-(2b+1)



We get rid of parentheses

3b-2b-1+2=0

We add all the numbers together, and all the variables

b+1=0

We move all terms containing b to the left, all other terms to the right

b=-1

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