(3b+5)+(d-2)=

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Solution for (3b+5)+(d-2)= equation:


Simplifying
(3b + 5) + (d + -2) = 0

Reorder the terms:
(5 + 3b) + (d + -2) = 0

Remove parenthesis around (5 + 3b)
5 + 3b + (d + -2) = 0

Reorder the terms:
5 + 3b + (-2 + d) = 0

Remove parenthesis around (-2 + d)
5 + 3b + -2 + d = 0

Reorder the terms:
5 + -2 + 3b + d = 0

Combine like terms: 5 + -2 = 3
3 + 3b + d = 0

Solving
3 + 3b + d = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 3b + -3 + d = 0 + -3

Reorder the terms:
3 + -3 + 3b + d = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 3b + d = 0 + -3
3b + d = 0 + -3

Combine like terms: 0 + -3 = -3
3b + d = -3

Add '-1d' to each side of the equation.
3b + d + -1d = -3 + -1d

Combine like terms: d + -1d = 0
3b + 0 = -3 + -1d
3b = -3 + -1d

Divide each side by '3'.
b = -1 + -0.3333333333d

Simplifying
b = -1 + -0.3333333333d

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