(3b+5)=(b-7)

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Solution for (3b+5)=(b-7) equation:



(3b+5)=(b-7)
We move all terms to the left:
(3b+5)-((b-7))=0
We get rid of parentheses
3b-((b-7))+5=0
We calculate terms in parentheses: -((b-7)), so:
(b-7)
We get rid of parentheses
b-7
Back to the equation:
-(b-7)
We get rid of parentheses
3b-b+7+5=0
We add all the numbers together, and all the variables
2b+12=0
We move all terms containing b to the left, all other terms to the right
2b=-12
b=-12/2
b=-6

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