(3b+q)/4+(b-5)/2=(4b-3)/8

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Solution for (3b+q)/4+(b-5)/2=(4b-3)/8 equation: 


x in (-oo:+oo)

(3*b+q)/4+(b-5)/2 = (4*b-3)/8 // - (4*b-3)/8

(3*b+q)/4+(b-5)/2-((4*b-3)/8) = 0

(3*b+q)/4+(b-5)/2+(-1*(4*b-3))/8 = 0

(2*8*(3*b+q))/(2*4*8)+(4*8*(b-5))/(2*4*8)+(-1*2*4*(4*b-3))/(2*4*8) = 0

2*8*(3*b+q)+4*8*(b-5)-1*2*4*(4*b-3) = 0

80*b-32*b+16*q-160+24 = 0

48*b+16*q-136 = 0

(48*b+16*q-136)/(2*4*8) = 0

(48*b+16*q-136)/(2*4*8) = 0 // * 2*4*8

48*b+16*q-136 = 0

x belongs to the empty set

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