(3b-2)(-3)=-9b+6

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Solution for (3b-2)(-3)=-9b+6 equation:



(3b-2)(-3)=-9b+6
We move all terms to the left:
(3b-2)(-3)-(-9b+6)=0
We get rid of parentheses
(3b-2)(-3)+9b-6=0
We multiply parentheses ..
(-9b+6)+9b-6=0
We add all the numbers together, and all the variables
9b+(-9b+6)-6=0
We get rid of parentheses
9b-9b+6-6=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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