(3b-2)/3=(b-2)/6

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Solution for (3b-2)/3=(b-2)/6 equation: 


b in (-oo:+oo)

(3*b-2)/3 = (b-2)/6 // - (b-2)/6

(3*b-2)/3-((b-2)/6) = 0

(3*b-2)/3+(-1*(b-2))/6 = 0

(6*(3*b-2))/(3*6)+(-1*3*(b-2))/(3*6) = 0

6*(3*b-2)-1*3*(b-2) = 0

15*b-6 = 0

(15*b-6)/(3*6) = 0

(15*b-6)/(3*6) = 0 // * 3*6

15*b-6 = 0

15*b-6 = 0 // + 6

15*b = 6 // : 15

b = 6/15

b = 2/5

b = 2/5

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