(3b-2)/4=(b-5)/12

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Solution for (3b-2)/4=(b-5)/12 equation: 



(3b-2)/4=(b-5)/12

We move all terms to the left:

(3b-2)/4-((b-5)/12)=0

We calculate fractions


3b/()+(-((b-5)*4)/()=0



We calculate terms in parentheses: +(-((b-5)*4)/(), so:

-((b-5)*4)/(

We multiply all the terms by the denominator


-((b-5)*4)



We calculate terms in parentheses: -((b-5)*4), so:

(b-5)*4

We multiply parentheses

4b-20

Back to the equation:

-(4b-20)



We get rid of parentheses

-4b+20

Back to the equation:

+(-4b+20)



We get rid of parentheses

3b/()-4b+20=0

We multiply all the terms by the denominator


3b-4b*()+20*()=0

We add all the numbers together, and all the variables

3b-4b*()=0

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