(3b-2)/6=(b-3)/12

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Solution for (3b-2)/6=(b-3)/12 equation: 


b in (-oo:+oo)

(3*b-2)/6 = (b-3)/12 // - (b-3)/12

(3*b-2)/6-((b-3)/12) = 0

(3*b-2)/6+(-1*(b-3))/12 = 0

(12*(3*b-2))/(6*12)+(-1*6*(b-3))/(6*12) = 0

12*(3*b-2)-1*6*(b-3) = 0

30*b-6 = 0

(30*b-6)/(6*12) = 0

(30*b-6)/(6*12) = 0 // * 6*12

30*b-6 = 0

30*b-6 = 0 // + 6

30*b = 6 // : 30

b = 6/30

b = 1/5

b = 1/5

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