(3b-2)12=(b-5)4

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Solution for (3b-2)12=(b-5)4 equation:



(3b-2)12=(b-5)4
We move all terms to the left:
(3b-2)12-((b-5)4)=0
We multiply parentheses
36b-((b-5)4)-24=0
We calculate terms in parentheses: -((b-5)4), so:
(b-5)4
We multiply parentheses
4b-20
Back to the equation:
-(4b-20)
We get rid of parentheses
36b-4b+20-24=0
We add all the numbers together, and all the variables
32b-4=0
We move all terms containing b to the left, all other terms to the right
32b=4
b=4/32
b=1/8

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