(3b-2)9=3(b-5)

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Solution for (3b-2)9=3(b-5) equation: 



(3b-2)9=3(b-5)

We move all terms to the left:

(3b-2)9-(3(b-5))=0

We multiply parentheses

27b-(3(b-5))-18=0



We calculate terms in parentheses: -(3(b-5)), so:

3(b-5)

We multiply parentheses

3b-15

Back to the equation:

-(3b-15)



We get rid of parentheses

27b-3b+15-18=0

We add all the numbers together, and all the variables

24b-3=0

We move all terms containing b to the left, all other terms to the right

24b=3

b=3/24

b=1/8

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