(3b-3)/4=(B-2)/8

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Solution for (3b-3)/4=(B-2)/8 equation: 


x in (-oo:+oo)

(3*b-3)/4 = (B-2)/8 // - (B-2)/8

(3*b-3)/4-((B-2)/8) = 0

(3*b-3)/4+(-1*(B-2))/8 = 0

(8*(3*b-3))/(4*8)+(-1*4*(B-2))/(4*8) = 0

8*(3*b-3)-1*4*(B-2) = 0

24*b-4*B-16 = 0

(24*b-4*B-16)/(4*8) = 0

(24*b-4*B-16)/(4*8) = 0 // * 4*8

24*b-4*B-16 = 0

x belongs to the empty set

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