(3b-4)/2=(b-3)/6

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Solution for (3b-4)/2=(b-3)/6 equation: 


b in (-oo:+oo)

(3*b-4)/2 = (b-3)/6 // - (b-3)/6

(3*b-4)/2-((b-3)/6) = 0

(3*b-4)/2+(-1*(b-3))/6 = 0

(6*(3*b-4))/(2*6)+(-1*2*(b-3))/(2*6) = 0

6*(3*b-4)-1*2*(b-3) = 0

16*b-18 = 0

(16*b-18)/(2*6) = 0

(16*b-18)/(2*6) = 0 // * 2*6

16*b-18 = 0

16*b-18 = 0 // + 18

16*b = 18 // : 16

b = 18/16

b = 9/8

b = 9/8

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